programming an audio signal using pic18f and Interrupt service Routine

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April 10, 2017 at 5:49 pm #13656

yamabonadine
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Hi,
I have in my pocession a microphone, an amplifier and a pic18f452. I have already connected the microphone to the amplifier. I did it on a turntable. I will connect the output of my microphone on the deck with an annalog port on the picdem Board and ground with ground on the picdem board. The channelA0 of the picdem board is reserved for the potentiometer so I have to use another port different from port A to connect the output of my Microphone, for exemple PORTC.
concerning programming I have to write a program that allows me to digitize this analog signal from the microphone and send it through the uart of my picdem board to a module blutooth HC05. the Picdem Board have an integrated ADC (10bit).
this is what i already do.can you suggest me anything? MY CODE

#pragma config OSC=HS,WDT=OFF,LVP=OFF // HS Oszillator, Watchdog Timer disabled, Low Voltage Programming
#include “p18f452.h”
#include “lcd.h”
extern void lcd_printf (const char* message);
extern void lcd_gotoxy (char row,char column);
extern void lcd_clear (void);
extern void lcd_init (void);
extern void lcd_byte (char num);
extern void lcd_int (int num);
extern void lcd_putc (char num);
 
void high_prior_InterruptHandler (void);
void low_prior_InterruptHandler (void);
 
unsigned int x=0, y=0;
unsigned char signal_in[];
unsigned char signal_out[];
unsigned char empfangspuffer,sendepuffer;
 
#pragma code high_prior_InterruptVector = 0x08
 
void high_prior_InterruptVector(void)
{
 _asm
 goto high_prior_InterruptHandler
 _endasm
}
 
#pragma code low_prior_InterruptVector = 0x18
 
void low_prior_InterruptVector(void)
{
 _asm
 goto low_prior_InterruptHandler
 _endasm
}
 
 
 
void init (void)
{
 lcd_init();
 lcd_clear();
 
/*UART serielle Schnittstelle initialisieren*/
 RCSTAbits.SPEN = 1; // Serial Port Enabled for TX & RX
 RCSTAbits.CREN = 0; // Continuous Receive Enabled
 TXSTAbits.BRGH = 1; // High Baud Rate Selected 
 SPBRG = 25; // Naud Rate = FOSC / (16(X+1)) // 4MHZ Asynch & HSpeed
 TXSTAbits.SYNC = 0;
/*ISR ,Interrupt Serielle Schnittstelle initialisieren*/
 PIE1bits.RCIE = 1; //Enable USART Interrupt
 PIR1bits.RCIF = 0; //Clear USART RX Interrupt Flag
 IPR1bits.RCIP = 1; //High Priority Enable
 TRISCbits.TRISC6 = 1; // 0b10111111;
//AD-Interrupts 
 PIR1bits.ADIF = 0; // Clear ADC Interrupt Flag
 IPR1bits.ADIP = 0; //SET to Low Priority
 PIE1bits.ADIE = 1; // Enable ADC Interrupt
// Allgemeine Interrupts
 RCONbits.IPEN = 1;
 INTCONbits.GIE =1;
 INTCONbits.PEIE =1;
//AD Einstellungen
 TRISAbits.RA0 = 1; //Port RA0 Poti auf Eingang setzen
 TRISEbits.RE0 = 1; //configure RE0 as input pin for Microphone
 ADCON1=0x8B; // Make RA0/AN0 and RE0 pin as analog pin 
 ADCON0=0xA9; //Fosc/32, Channel 5
 ADCON0bits.ADON = 1; // Enable ADC
}
 
/* UART Receive*/
#pragma code
#pragma interrupt high_prior_InterruptHandler
 
 
void high_prior_InterruptHandler(void)
{
 
 //code
 
}
 
/*sendung mit uart TX*/
#pragma code
#pragma interrupt low_prior_InterruptHandler
 
void low_prior_InterruptHandler(void)
{
 //code
}
 
/*AD Wandlung*/
#pragma code
#pragma interrupt low_prior_InterruptHandler
 
void low_prior_InterruptHandler(void)
{
 if(PIR1bits.ADIF == 1) //A/D-Wandlung starten
 {
 x = ADRESH; //A/D-Ergebnis Bit 2 bis 10
 y = ADRESL;
 PIR1bits.ADIF = 0;
 ADCON0bits.GO_DONE = 1; // ADC neu starten
 }
 
 
void main()
{
 
}
i want your help for Programming please.
Regards
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